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chegg cracked apk for androidQ:

SELECT MAX(id) where a column is not null

I have a question regarding the sql statement
SELECT MAX(id) from table where name like ‘%prod%’

If I have rows that look like this
id name
1 W300C
2 W400C
3 W600C
4 W400C2

The query will return only MAX(id) which is 4 (whereas the correct max is 3)
How would I modify the statement to get the correct value 3?

I think you are looking for:
SELECT max(id)
FROM (SELECT id, name,
MAX(id) over (PARTITION BY name) as max_id
FROM table
) t
WHERE name LIKE ‘%prod%’

This will find the next max after the current max.
SELECT *
FROM (SELECT id, name, MAX(id) as max_id
FROM table
) v
WHERE name LIKE ‘%prod%’ AND
MAX(id) + 1 = max_id

This is equivalent to the following, but not sure what the point of the variables name and max_id are:
SELECT *
FROM (SELECT id, name, max(id) as max_id
FROM table
) v
WHERE name LIKE ‘%prod%’ AND
max_id + 1 = max_id

(-1/12) assuming j is positive.
j**(-19/12)
Simplify ((z/(z/(z/(z/z**(4/7))))*z)/(z/(z/z**(-1/4)*z)))**37 assuming z is positive.
z**(1811/28)
Simplify ((w*w**(-1/4))/w)**(1/37)/(w/(w*w**3/w)*w**(-2/15)) assuming w is positive.
w**(4813/2220)
Simplify (z*z
f30f4ceada

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